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14p^2+82p+60=0
a = 14; b = 82; c = +60;
Δ = b2-4ac
Δ = 822-4·14·60
Δ = 3364
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3364}=58$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(82)-58}{2*14}=\frac{-140}{28} =-5 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(82)+58}{2*14}=\frac{-24}{28} =-6/7 $
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